Alternative solution

I wrote an alternative solution; I'm submitting it here in case someone wishes to put it on the main page. Corrections/comments/style fixes greatly appreciated. JesseW 20:00, 9 July 2007 (BST)

/* strend(char * s, char * t) -- return true if t ends s.*/
/* use pointers */
/* basic code outline (non-pointer version) copied from strcat shown in K&R, page 48 */
int mystrend(char *s, char *t)
{
  //printf("mystrend(\"%s\", \"%s\")\n",s,t);
  char * start_of_t = t;
  while (*(s++) != '\0') /* find end of s */
    ;//printf("!%c!",*s); 
  //printf("\n");
  while (*(t++) != '\0') /* find end of t */
    ;//printf("!%c!",*t); 
  //printf("\n(%i)==(%i):%i (%i)>=(%i):%i\n",*(s-1), *(t-1), *(s-1)==*(t-1), (int)t, (int)start_of_t, t>=start_of_t);
  while (*(--s) == *(--t) && t >= start_of_t) /* move backwards as long as t and s are identical, */
    ;//printf("!%c:%c!",*s, *t);                                          /* till you get to the beginning of t. */
  //printf("\n %i==%i\n", (int)t, (int)start_of_t);
  if (t+1 == start_of_t) /* if we made it all the way through t; return true. */
    return 1;
  return 0;
}

int main(void) {
  
  printf("(normal success) 1 == %i\n",mystrend("abcdef", "def"));
  printf("(empty t) 1 == %i\n",mystrend("abcdef", ""));
  printf("(last char wrong) 0 == %i\n",mystrend("abcdeg", "def"));
  printf("(first char wrong) 0 == %i\n",mystrend("abcqef", "def"));
  printf("(empty s) 0 == %i\n",mystrend("", "def"));
  printf("(both empty) 1 == %i\n",mystrend("", ""));
}

Added a new solution without writing it in the summary subject

I would thank suggestions. I'm learning.
Greetings,
Jose G. López