Ex No |
Pg No |
Exercise |
Solution |
Solved by |
---|
1 | 36 |
Write a program to determine the ranges of char , short , int , and long
variables, both signed and unsigned , by printing appropriate values from
standard headers and by direct computation. Harder if you compute them: determine
the ranges of the various floating-point types.
|
Listing krx201 |
Rick Dearman |
2 | 42 |
Write a loop equivalent to the for loop above without using && or || .
|
Listing krx202 |
"flippant_squirrel" (!) and Craig Schroeder |
3 | 46 |
Write the function htoi(s) , which converts a string of hexadecimal
digits (including an optional 0x or 0X) into its equivalent integer
value. The allowable digits are 0 through 9, a through f, and A through F .
|
Listing krx203 |
Richard Heathfield |
4 | 48 |
Write an alternate version of squeeze(s1,s2) that deletes each character
in the string s1 that matches any character in the string s2 .
|
Listing krx204 |
Richard Heathfield |
5 | 48 |
Write the function any(s1,s2) , which returns the first location in the
string s1 where any character from the string s2 occurs, or -1 if s1
contains no characters from s2 . (The standard library function strpbrk does
the same job but returns a pointer to the location.)
|
Listing krx205 |
The pedestrian solution is Richard Heathfield's, and the clever one is by Partha Seetala. |
6 | 49 |
Write a function setbits(x,p,n,y) that returns x with the n bits that
begin at position p set to the rightmost n bits of y, leaving the other
bits unchanged.
|
Listing krx206 |
Richard Heathfield |
7 | 49 |
Write a function invert(x,p,n) that returns x with the n bits that begin at
position p inverted (i.e., 1 changed into 0 and vice versa), leaving the others unchanged.
|
Listing krx207 |
Gregory Pietsch |
8 | 49 |
Write a function rightrot(x,n) that returns the value of the integer x rotated to the
right by n bit positions.
|
Listing krx208 |
Gregory Pietsch |
9 | 51 |
In a two's complement number system, x &= (x-1) deletes
the rightmost 1-bit in x . Explain why. Use this observation to write a
faster version of bitcount .
|
Listing krx209 |
Gregory Pietsch |
10 | 52 |
Rewrite the function lower, which converts upper case letters
to lower case, with a conditional expression instead of if-else .
|
Listing krx210 |
Bryan Williams |